A die is thrown. What is the probability of getting a multiple of three on the upper face
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Answered by
13
Answer:
Total no. of outcomes; n(s) = 6 [ ie 1, 2, 3, 4, 5, 6]
No. Of favorable outcomes; multiples of 3 in the dice n(e) = 2 [3, 6]
P(getting a multiple of 3) = n(e)/ n(s)
= 2/6 =1/3
Answered by
1
Answer:
1/3
Step-by-step explanation:
nos. on dice which are multiples of 3 are 3 and 6.
total outcomes are 6
probability is 2/6 i. e. 1/3
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