Question

A die is thrown . what is the probability of getting a prime number.
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Answer 1

Step-by-step explanation:

ANSWER

Prime numbers on a die are 2,3 and 5

So, P(getting a prime number) = 3/6 = 1/2

Answer 2

Answer:

The answer will be ½.

Step-by-step explanation:

The Prime Numbers in the dice are : 2, 3 and 5

And the Non–Prime Numbers are : 1, 4 and 6

Now Maximum number a Dice contain = 6

Now, probability of Getting a prime number =

$\frac{the \: required \: event}{the \: maximum \: event}$

So the equation =

$\frac{3}{6} \: \:times$

And if we reduce it, we will get ½ which is the correct answer.

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