Question

a die is thrown . what is the probality o getting i] a prime number? ii] anumber greater than 4?iii] a number not greater than 5?

Answer 1

may it will help you hope it will be helpfull

Answer 2

Hey!

Ans i) prime numbers :- 2 , 3 , 5 , 7 ,11......

$\: probability \: =\frac{number \: of \: observations \: to \: make \: an \: event}{total \: number \: of \: observations}$

so, in a die there are 3 prime numbers i.e, 2 , 3 and 5

so,

= $\frac{3}{6}$

denominator is 6 because the total number of observations in a die are 6.

so,

= $\frac{3}{6}$

= $\frac{1}{2}$

so, you have 1/2 probability of getting a prime number.

Ans ii) there are only 2 numbers greater than 4 in a die i.e, 5 and 6

so,

= $\frac{2}{6}$

= $\frac{1}{3}$

so, you have 1/3 chance of getting a number greater than 4.

Ans iii) there are 5 numbers which are not greater than 5 .

so,

= $\frac{5}{6}$

I hope this answers your question!