Question

A die is tossed once. Find the probability of getting (i) a number 5 (ii) a prime number (iii) an odd number (iv) a number greater than 6.​

Answer 1

Answer:

I)1/6

ii)1/2

iii)1/2

iv)0/6=0

Answer 2

Answer:

•1/6 = probability of getting 5

•1/2 = probability of getting prime no.

•1/2 = probability of getting an odd no.

•1 = probability of getting greater no. than 6

pls mark it brainliest , if it helped u out ☝️