Math, asked by srinivassndpe920f, 11 months ago

a die numbered square root 1, square root2, square root3, square root4, square root5, square root 6 find the probability of irrational number​

Answers

Answered by varunshastry05
6

Answer:

4/6=2/3

Step-by-step explanation:

square roots of 2 3 5 and 6 are irrational....

Cheers

Answered by inido32
10

Answer:

probability of getting an irrational number=4/6

=2/3

Step-by-step explanation:

Total outcomes=6

since √2,√3,√5 and √6 are irrational numbers

S{√2,√3,√5,√6}

Number of favourable outcomes =4

P(E)=4/6

=2/3 (multiply by 2/2)

Hope it helps

All the best!!!!!

Similar questions