English, asked by sonaliash2002, 9 months ago

describe the house of the laputa ​

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Answered by mustafashaikh93462
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Answered by Anonymous
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The island of Laputa is described as being exactly circular and 4.5 miles (7.2 km) in diameter, giving an area of roughly 10,000 acres (4,100 ha). The island was 300 yards (270 m) thick, and comprised a bottom plate of adamant 200 yards thick, above which lay "the several minerals in their usual order", topped with "a coat of rich mould 10 or 12 ft deep".

In shape the upper surface sloped down from circumference to centre, causing all rain to form rivulets into the centre where four large basins half a mile in circuit lie 200 yards from the absolute centre. In the centre of the island itself was a chasm 50 yards in diameter continuing down into a dome extending 100 yards into the adamantine surface. This dome served as an astronomical observatory, and also contained the lodestone which enabled the island to fly and move above the realm.

Laputa was located above the realm of Balnibarbi, which was ruled by its king from the flying island. Gulliver states the island flew by the “magnetic virtue” of certain minerals in the grounds of Balnibarbi which did not extend to more than four miles above, and six leagues beyond the extent of the kingdom[1], showing the limit of its range. The position of the island, and the realm below, is some five days' journey south-south-east of Gulliver's last known position, 46N, 183E (i.e. east of Japan, south of the Aleutian Islands) down a chain of small rocky islands.

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