Math, asked by rahulkumar4453, 1 year ago

A die was rolled 100 times and the number of time 6appeared was noted. if the probability of getting a 6 be 2/5 how many times did 6come up?

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Answered by pragati29716611
2
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A die was rolled 100 times and the number of time 6 came up was noted. If the experimental probability calculated from this information is 2/5, then how many times 6 came up? Justify your answer.

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vivek0405

vivek0405 Ambitious

2 \div 5 = x + \div 100 \\ x = 2 \div 5 \times 100 \\ x = 40

Where x is no of times 6occured

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VarunJogi428 Ambitious

Answer:

Step-by-step explanation:

Mark it as brainliest..

Here, total number of trials = 100

Let x be the number of times occuring 6.

We know, Probability of an ever = Frequency of the event occuring / Total number of trials

⇒ x / 100 = 2 / 5 [∵ Probability is given]

⇒ x = 40

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Answered by aanishkakaushik
0

Answer:

40 times

Step-by-step explanation:

total no. of outcomes= 100

probability of 6= 2/5

P(6)= number of times 6 came up

         total no. of outcomes

=2= number of times 6 came up

 5                       100

=200=5(number of times 6 came up)

=40=number of times 6 came up

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