Math, asked by rajeswari266, 4 months ago


A digit is 5 less than 4 times the other digit. The sum of the both the digits is 50.calculate the difference
between the two digits.​

Answers

Answered by Anonymous
2

Answer:

There’s more than one way to solve it.

Method 1:

You can look at cases. First of all, it is less than 50, so the first digit is either 1,2,3, or 4.

Assume the first digit is 1: The maximun sum we can get in this case is 1 + 9 = 10. Not the case.

Assume the first digit is 2: The maximum sum we can get in this case is 2 + 9 = 11. Not the case.

Assume the first digit is 3: The sum 3 + 9 = 12 satisfies the first condition, but 9–3 is not 4! Not the case.

Assume the first digit is 4: The sum 4 + 8 satisfies the first condition AND 8–4 =4. BINGO. The number is 48.

Method 2:

Use a system of equations.

Assume one of the digits is x and the second is y.

x + y = 12.

y - x = 4 (or x-y =4)

Add the equations: 2y = 16 or y = 8.

Substitute y in any of the two equations to get x = 4.

Now we got the two digits: 4 and 8.

84 is a rejected value since it is greater than 50. This leaves us with 48.

Step-by-step explanation:

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