A digit is 5 less than 4 times the other digit . the sum of the both the digit is 50 . calculate the difference between the two digit .
Answers
Answer:
y=4
Step-by-step explanation:
Let the two-digit number be xy
sum, x + y = 12 and
Difference, x - y = 4.
x + y = 12………equation i
x - y = 4…………equation ii.
Solving the simultaneous equations using elimination method. We have,
2x = 16 ( by addition of the equations)
x = 16/2 = 8. Substituting 8 for x in any of the two equations above. We have,
8 + y = 12 ( using equation i )
y = 12 - 8 =4
Therefore, x=8 and y= 4 . Since the number is less than 50, it means it can only be 48 and not 84.
Hence the two-digit number is 48.
Confirmation:summation x + y = 8 + 4 =12, difference x - y = 8 – 4 = 4 .
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Answer:
Method 1:
You can look at cases. First of all, it is less than 50, so the first digit is either 1,2,3, or 4.
Assume the first digit is 1: The maximun sum we can get in this case is 1 + 9 = 10. Not the case.
Assume the first digit is 2: The maximum sum we can get in this case is 2 + 9 = 11. Not the case.
Assume the first digit is 3: The sum 3 + 9 = 12 satisfies the first condition, but 9–3 is not 4! Not the case.
Assume the first digit is 4: The sum 4 + 8 satisfies the first condition AND 8–4 =4. BINGO. The number is 48.
Method 2:
Use a system of equations.
Assume one of the digits is x and the second is y.
x + y = 12.
y - x = 4 (or x-y =4)
Add the equations: 2y = 16 or y = 8.
Substitute y in any of the two equations to get x = 4.
Now we got the two digits: 4 and 8.
84 is a rejected value since it is greater than 50. This leaves us with 48.
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