Question

.A digital in the ten's place of a two digit number is twice the digit in the unit's place. One-fourth of the sum of the original number and the number obtained by reversing the order of the digits is 33 . Find the original number.​

Answer 1

Step-by-step explanation:

Let x be the number at the unit's place and y be the number at the ten's place.

Two digit number = 10y + x

 

According to the conditions,

y = 2x 

2x - y = 0 ...(i)

 

 

10x + y + 10y + x = 66

x + y =11 ....(ii)

 

Solve (i) and  (ii), we get

x = 2 and y = 4

Two digit number = 10y + x = 42

Hope it helps u...........

Answer 2

f the number obtained by interchanging the digits is added to the original number, the sum is 66. ... Let the tens digit be x and the units digit be y. ... Frim equation 1 x=2y ... $\sqrt[3]{216}$​ Each year, the number of adults who get the flu to those who do not is 1:9 and the ... Sum of two numbers is 21 .

2 answers