Question

A digits of a positive number of three digits in an ap .Their sum is 15 ..The number obtained by reversing the digit is 594 less than the original number .Find the numbers

Answer 1

Answer:

Step-by-step explanation:

Ap is c ,b,a

C,c+d,c+2d

C+c+d+c+2d =15

3c+3d=15

C+d =5

Now 100a +. 10 b+c=100 c+10b +a +594

So 99a-99c =594

So a-c =6

So C+2d -c =6

2d =6

D=3

So c+d =5

C=2

So the numbers are 8 5 2