Question

A dilute aqueous solution of sodium fluoride is electrolysed ; the products at the anode and cathode are

Answer 1

$\underline{\underline{\Huge\mathfrak{Answer}}}$

Electrolyte: NaF (+H20) aqueous
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Electrolytic Reaction:

NaF⇌ (Na+) + (F-)
H2O⇌ (H+) + (OH-)
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Reaction at cathode:

H+ and Na+ cations come towards the cathode but H+ ions are deposited.

(H+) + e = H
H+H= H2 (Hydrogen gas)
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Reaction at anode:

OH- and F- ions comes towards the anode but only OH- ions gets deposited at the anode.

(OH-) - e= OH
OH+OH= H2O + O
O+O=O2 (Oxygen gas)
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Therefore, Products formed are:
a). Hydrogen:- Cathode
b). Oxygen:- Anode