A dipole with a dipole moment of magnitude p is in stable equilibrium in an electrostatic field of magnitude E . Find the word done in rotating this dipole to its position of unstable equilibrium.
Answers
Answered by
81
For stable equilibrium the angle between p and E , θ₁ = 0°
For unstable equilibrium,θ₂ = 180°
Work done in rotating the dipole from angle θ₁ to θ₂
W = pE(cosθ₁-cosθ₂) = pE(cos0°-cos180°)
= 2pE.
For unstable equilibrium,θ₂ = 180°
Work done in rotating the dipole from angle θ₁ to θ₂
W = pE(cosθ₁-cosθ₂) = pE(cos0°-cos180°)
= 2pE.
Answered by
51
Hi friend,
The work done in rotating the dipole is
W= P× E Cos (theta)
For stable it moves on uniform direction :- at 0°
For unstable it rotates at 180°
:-W= PE [cos theta (1)-cos theta(2)]
W=PE( cos 0°- cos 180°)
W= PE (1-(-1)
W= 2PE
Hope this helped you a little!!!
The work done in rotating the dipole is
W= P× E Cos (theta)
For stable it moves on uniform direction :- at 0°
For unstable it rotates at 180°
:-W= PE [cos theta (1)-cos theta(2)]
W=PE( cos 0°- cos 180°)
W= PE (1-(-1)
W= 2PE
Hope this helped you a little!!!
Similar questions