Question

A direct current/deposits 54 g/of ag during/elecyrolysis. the sane/quantity of electricity/qould/deposit aluminium from/aluminium chloride i molten state would be equal to

Answer 1

Ag+ + e = Ag

Al3+ + 3e = Al

1 mole of electrons deposit 1 mole of Ag

3 moles of electrons deposit 1 mole of Al

The number of moles of Al deposited is 1/3  the number of moles of Ag deposited


Number of moles of Ag = 54/108 = 0.5

Number of moles of Al deposited = 1/3 x 0.5 = 1/6 moles


Mass of Al = 1/6 x 27

                  = 4.5 g

Answer 2

Answer:

4.5 g

Explanation:

1/3 ×mass of ag/ atomic mass of ag

1/3× 54/108

moles of Al= 1/6

mass of Al= 1/6 × 27

=4.5 g