A disc and a ring of same mass are rolling and if their kinetic energies are equal, then the ratio of their velocities will be
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mass of disc =mass of ring
kinetic energy of disc =kinetic energy of ring
1/2intomass of disc into (velocity of disc)
*2upon 1/2intomass of ring into (velocity of ring) *2
(velocity of disc) *2 upon ( velocity of ring)*2
kinetic energy of disc =kinetic energy of ring
1/2intomass of disc into (velocity of disc)
*2upon 1/2intomass of ring into (velocity of ring) *2
(velocity of disc) *2 upon ( velocity of ring)*2
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Answer:
v1/v2=(4/3)^1/2
Explanation:
As it is given kinetic energies are same
therefore
3/4mv1^2=mv2^2
v1/v2=(4/3)^1/2
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