A disc is freely rotating with angular speed omega on a smooth horizontal plane if it is too good at average page p and rotates without counting about a point on its circumference its angular speed after impact will be equal to
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In short, it is expected that the book will embrace the requirements of the .... Motion of Rotation Under Constant Angular Acceleration.
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Explanation:
During the impact,the impact of forces pass through the point P.Therefore,the torque produced by it about P is equal to zero. Consequently the angular momentum of the disc about P,just before and after the impact remains the same.
L1=L2____eqn1
Where L1=angular momentum of the disc about P just before the impact
Iœ(Iomega)=1/2mr^2œ(Omega)
L2=angular momentum of the disc about P just after the impact
Iœ(Omega)= (1/2mr^2+mr^2)œ
= 3/2mr^2œ'
3/2mr^2œ' = mr^2œ
œ'=1/3œ
Hope it helps
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