Question

A disc of radius 0.1m rolls without sliding on a horizontal surface with a velocity of 6m/s. It then ascends a smooth continuous track. The height upto which it will ascends is​

Answer 1

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Correct Answer

For an object rolling without slipping, linear translation velocity v and angular velocity of rotation ω are related as,

v = ω×R, where R is radius of the object.

v = 36 km/hr = 36 × (5/18) = 10 m/s

ω = 10×1 = 10 rad/s

1 revolution = 2π rad /s

hence ω = 10/2π revoltions per second.

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Answer 2

Answer:

1.8 m

Explanation:

mgh= 1/2 mv^2

which gives  h= 1.8 m