a disc of weight 200 newton and radius 4 cm.A rectangular bar of dimensions 5×4×3cm of weight 110 newton.A cube of esge 5cm and weight 120 newton,are placed on a table.If P1,P2andP3 are the pressures exerted by respectively then compare P1,P2 and P3
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Pressure exerted by an object through its base :
weight in Newtons / surface area of its base in contact with the table.
Pressure due to the disc : P1 = 200 N/ π 0.04² m²
bar: P2 = 110 N / (0.05 * 0.04 m²)
cube: P3 = 120 N / (0.05 * 0.05 m²)
To convert the pressure in to dynes, multiply by 10⁵.
Compare: P1 : P2 : P3 = 25 : 11 π : 9.6 π
weight in Newtons / surface area of its base in contact with the table.
Pressure due to the disc : P1 = 200 N/ π 0.04² m²
bar: P2 = 110 N / (0.05 * 0.04 m²)
cube: P3 = 120 N / (0.05 * 0.05 m²)
To convert the pressure in to dynes, multiply by 10⁵.
Compare: P1 : P2 : P3 = 25 : 11 π : 9.6 π
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