Question

A dishonest dealer marks up the price of his goods by 20% and gives a discount of 10% to the customer. besides, he also cheats both his supplier and his buyer by 100 grams while buying and selling 1 kilogram. find the percentage profit earned by the shopkeeper. gateoverfow

Answer 1

While buying,

He buys 1100 gram instead of 1000gram.
Suppose he bought 1100 grams for Rs. 1000.

While selling,

He sells only 900 grams when he takes the money for 1 kg.
Now, according to the problem,
he sells at an 8% profit (20% markup, 10% discount).
Hence, his selling price is Rs. 1080 for 900 grams.
Now,
1100grams for Rs. 1000
Hence, 1188 grams for Rs. 1080
Selling: 900 grams for Rs. 1080.
Hence, % profit = 288/900 = 32%.

Answer 2

Answer:

32%

Step-by-step explanation:

Suppose he bought 1100 grams for Rs. 1000

He sells only 900 grams when he takes the money for 1 kg

he sells at a 8% profit (20% markup, 10% discount)

(100*20%=120 , 120*10%= 112 ,   120-112=8%)

Hence, his selling price is Rs. 1080( as 1000*8%) for 900 grams

He buys 1100 gram instead of 1000 gram

1100 grams for Rs. 1000 (as compare first line)

Hence, 1188 grams( as 1100*8%=1188) for Rs. 1080 (as 1000*8%)

Selling: 900 grams for Rs. 1080

so, actually selling of 1188 grams??

actual (1188*1080)/900= Rs. 1425.6

profit =1425.6-1080= Rs. 345.6 out of Rs 1080

% of profit = (345.6/1080)*100=32%