Math, asked by kk2911, 6 months ago

A dishonest dealer professes to sell at cost price but uses a 900 gram weight instead of a 1 kilogram weight. Find the percent profit for the dealer.​

Answers

Answered by monikaaadi81
8

Answer:

Percentage Gain = [(Selling Price - Cost Price) * 100] / Cost Price

Suppose the cost price of 1g is x.

Therefore,

Selling Price = 1000x (because he claims to be giving 1kg weight)

Cost Price = 900x (because the goods he actually gives is 900g)

So,

Percentage Gain = [(1000x - 900x) * 100] / 900x

Percentage Gain = [(100x) * 100] / 900xPercentage Gain = 10000x / 900x

Percentage Gain = 100/9 = 11.11%

Hence, his percentage gain is 11.11%

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Answered by Anonymous
3

Step-by-step explanation:

Percentage Gain = [(Selling Price - Cost Price) * 100] / Cost Price

Suppose the cost price of 1g is x.

Therefore,

Selling Price = 1000x (because he claims to be giving 1kg weight)

Cost Price = 900x (because the goods he actually gives is 900g)

So,

Percentage Gain = [(1000x - 900x) * 100] / 900x

Percentage Gain = [(100x) * 100] / 900x

Percentage Gain = 10000x / 900x

Percentage Gain = 100/9 = 11.11%

Hence, his percentage gain is 11.11%

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