Math, asked by guptamegha280, 11 months ago

a dishonest dealer sells the goods at 6 1/4% loss on cost price but uses 12 1/2 % less weight. what is his percentage profit or loss? ​

Answers

Answered by sanjeevk28012
2

Answer:

The percentage profit of dishonest dealer is 100% .

Step-by-step explanation:

Given as :

The dishonest dealer sell good at 6 \dfrac{1}{4} %  = \dfrac{25}{4} % loss on cost price

The dishonest seller uses 12 \dfrac{1}{2} % = \dfrac{25}{2} % less weight

So, The profit percentage = p % = \dfrac{\frac{25}{2} - \frac{25}{4}  }{\frac{25}{4} }

i.e p% = \dfrac{\frac{50-25}{4} }{\frac{25}{4} }

Or, p% = \dfrac{\frac{25}{4} }{\frac{25}{4} }

Or, p% = 1

So, The percentage % = p = 100

Hence, The percentage profit of dishonest dealer is 100% . Answer

Answered by Anonymous
37

Answer: 7 1/7 %

Step-by-step explanation:

let the CP of 1kg = 100

12 1/2% less, i.e 1000g - 125g = 875g

6 1/4% loss on CP, i.e 100 - 6.25 = Rs. 93.75

Then, SP of 1kg = 93.75/875 X 1000 = 100 1/14

lets calculate profit % =  (1/14 X 100) % = 7 1/7 %

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