Question

A dishonest milkman purchased milk at rs 10 per litre and mixed 5 litres of water in it .By selling the nixture at the rate of rs.10 per litre he earns a profit of 25%.the quantity of mixture he had?​

Answer 1

here u go..

Given:-

The C.P. of pure milk is given as = Rs. 100 per litre

The C.P. of pure milk is given as = Rs. 100 per litreSince pure water doesn’t cost anything ∴ C.P. of pure water = Rs. 0

The C.P. of pure milk is given as = Rs. 100 per litreSince pure water doesn’t cost anything ∴ C.P. of pure water = Rs. 0The S.P. of the mixture = Rs. 100 per litre

The C.P. of pure milk is given as = Rs. 100 per litreSince pure water doesn’t cost anything ∴ C.P. of pure water = Rs. 0The S.P. of the mixture = Rs. 100 per litreProfit% = 25%

To find:

To find:The original quantity of mixture that the milkman had=

Solution:

Solution:We know that pure water doesn’t cost anything

Solution:We know that pure water doesn’t cost anything∴ The cost price of pure water will be = Rs. 0

Solution:We know that pure water doesn’t cost anything∴ The cost price of pure water will be = Rs. 0According to the question, we can get the cost price of the mixture as:

$cp = \frac{100}{100 + profit} \times 10$

$\frac{100}{100 + 25} \times 10$

$\frac{100}{125} \times 10$

$= 8 \: litres$

= Rs. 8 per litre

Now, by using the method of mixture and alligations, we get

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)(80-0) (100 - 80)

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)(80-0) (100 - 80) 80 20

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)(80-0) (100 - 80) 80 20∴ Milk:Water = 80:20 = 4:1

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)(80-0) (100 - 80) 80 20∴ Milk:Water = 80:20 = 4:1From the ratio we can see that for every 4 litres of milk, 1 litre of water is mixed in the mixture.

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)(80-0) (100 - 80) 80 20∴ Milk:Water = 80:20 = 4:1From the ratio we can see that for every 4 litres of milk, 1 litre of water is mixed in the mixture. So, we can conclude that, for 10 litres of water added there will be 4*10 = 40 litres of milk

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)(80-0) (100 - 80) 80 20∴ Milk:Water = 80:20 = 4:1From the ratio we can see that for every 4 litres of milk, 1 litre of water is mixed in the mixture. So, we can conclude that, for 10 litres of water added there will be 4*10 = 40 litres of milk∴ Resultant mixture = 10 + 40 = 50 litres

= Rs. 8 per litreNow, by using the method of mixture and alligations, we getMilk Water100 0 80(Mixture)(80-0) (100 - 80) 80 20∴ Milk:Water = 80:20 = 4:1From the ratio we can see that for every 4 litres of milk, 1 litre of water is mixed in the mixture. So, we can conclude that, for 10 litres of water added there will be 4*10 = 40 litres of milk∴ Resultant mixture = 10 + 40 = 50 litresThus, the amount of mixture the milkman had with him to sell was 50 litres.