the stationary point of y=sinx are
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Given : y = Sinx
To find : Stationary point
Solution:
The stationary points will be the points where the gradient is zero:
y = sinx
dy/dx = Cosx
Cosx = 0 for x = (2n + 1)π/2 n ∈ Z
n = 0 => Sinπ/2 = 1 = (-1)⁰
n = 1 => Sin3π/2 = -1 = (-1)¹
n = 2 => Sin5π/2 = 1 = (-1)²
Sin ( (2n + 1)π/2 ) = (-1)ⁿ
Hence stationary point is ( (2n + 1)π/2 , (-1)ⁿ )
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