A dishonest salesman sells his goods at a profit of 20%
while also using a weighing machine that weighs the
good 20% less in weight than marked. What is his total
percent gain?
Answers
Let us assume that 1000 g of goods cost Rs. 100.
Since he makes a Profit of 20%, the Selling Price would be:
⟹Profit%=
CP
(SP−CP)
×100
⟹20=
100
SP−100
×100
⟹20=SP−100
⟹SP=100+20=
Rs.120
Hence for 1000 grams of goods, he sells them for Rs. 120 by which he earns a profit of 20%.
Now, it is given that, he also uses a weighing machine which weighs the goods 20% less than the original weight.
Hence 1000 g of goods in his weighing machine would weigh:
Hence his machine would show the weight of 800 g to be equal to 1000 g.
Therefore, for 1000 g = Rs. 120, then for 800 g the actual selling price would be:
⟹SP for 800 g =
1000
800×120
⟹ SP for 800 g=
Rs.96
But, the shopkeeper is selling it for Rs. 120. Hence profit made here is:
\begin{gathered}\begin{gathered}\implies Profit\: \% = \dfrac{120 - 96}{96} \times 100\\\\\\\implies Profit\: \% = \dfrac{24}{96} \times 100\\\\\\\implies Profit\: \% = \dfrac{100}{4} \\\\\\\implies Profit\: \% = \boxed{ \bf{ 25\:\%}}\end{gathered} \end{gathered}
⟹Profit%=
96
120−96
×100
⟹Profit%=
96
24
×100
⟹Profit%=
4
100
⟹Profit%=
25%
\sf \: Therefore \: the \: net \: profit \:gained \: by \: the \: dishonest \: shopkeeper \: is \: 25%Thereforethenetprofitgainedbythedishonestshopkeeperis25