Math, asked by ajith3384, 11 months ago

A dishonest shopkeeper professes to sell pulses at his cost price but uses a false weight of 950 gm for each kilogram. Find his gain percent

Answers

Answered by nidaeamann
9

Answer:

Gain percent of shopkeeper is 5

Step-by-step explanation:

The shopkeeper is using wrong weight of 950 gram against the weight of 1000 gram. It means that when is selling something to a customer for 1000 grams, he is actually giving 950 and saving 50 grams out of every 1000 grams sold. So the percentage of his saving would be;

Saving = 50 / 1000 x 100 = 5 %

Gain percent of shopkeeper is 5

Answered by roshinik1219
20

Gain percent = \frac{100}{19} \%

Step-by-step explanation:

We know that,      

                      1kg = 1000gm

so,

Original weight = 1000gm

The shop keeper uses  950 gm instead of 1000gm

False weight or quantity given to customer  = 950gm

Difference in weights = 1000 - 950

                                   = 50gm

                         Profit in \% = \frac{1000 - 950}{950} \times 100

                                              = \frac{50}{950} \times 100

                                             = \frac{100}{19}  \%

The shopkeeper gain \frac{100}{19} \% by using false weight.

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