A displacement vector r has a magnitude of 25m and makes an angle of 210° with the x-axis. It's y-component is
Answers
A displacement vector r has magnitude of 25m and makes an angle of 210° with x-axis as shown in figure.
so, it makes an angle 30° with negative part of x-axis.
then, in vector form we can write displacement vector
so, it's y - component = -|r|sin30°
= -25 × 1/2 = -12.5 m [ negative sign indicates that negative part of y-axis ]
hence, magnitude of y - component = 12.5m
Explanation:
Answer; 12.5j cap
A displacement vector r has magnitude of 25m and makes an angle of 210° with x-axis as shown in figure.
so, it makes an angle 30° with negative part of x-axis.
then, in vector form we can write displacement vector \vec{r}=-|r|cos30^{\circ}\hat{i}-|r|sin30\hat{j}
r
=−∣r∣cos30
∘
i
^
−∣r∣sin30
∘
j
^
so, it's y - component = -|r|sin30°
Always y axis will be j cap
We have to find the y axis component so we have to take sin thetha
= -25 × 1/2 = -12.5 m [ negative sign indicates that negative part of y-axis ]
hence, magnitude of y - component = 12.5j cap