Question

Three randomly chosen non–negative integers x, y and z are found to satisfy the equation x + y + z = 10. Then the probability that z is even, is

(A) $\frac{36}{55}$

(B) $\frac{6}{11}$

(C) $\frac{1}{2}$

(D) $\frac{5}{11}$

Answer 1

Answer:

Step-by-step explanation: