a distance of a chord AB from the centre of a circle is 8cm.length of a chord AB is 12cm.find the diameter of a circle.
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The answer of this question is 20 cm
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as perpendicular from centre to chord divides the chord in 2 equal parts.
radius= √(od ^2 +ab/2 ^2)
r= √(8 ^2 + 6 ^2)cm
r= √(64 + 36)cm
r= √( 100)cm
r= 10 cm.
radius= √(od ^2 +ab/2 ^2)
r= √(8 ^2 + 6 ^2)cm
r= √(64 + 36)cm
r= √( 100)cm
r= 10 cm.
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