Question

A divenging lens of focal length 5cm forms an image 10 cm from the lens how far is the object is placed from the lens? ​

Answer 1

Answer:

10cm

Explanation:

Given:

Diverging lens = concave lens

f = -5cm

v = -10cm (Diverging lens always forms image on the object side only)

To find:

u = distance from the lens

Formula:

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

Solution:

So, according to the formula, on substituting the values, we get,

$\frac{1}{ - 5} = \frac{1}{ - 10} - \frac{1}{u}$

$\frac{1}{u} = \frac{1}{5} - \frac{1}{10}$

$\frac{1}{u} = \frac{2}{10} - \frac{1}{10}$

$\frac{1}{u} = \frac{1}{10}$

$u = {10}$

Distance of object from lens is 10cm

Hope it helps

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