Question

. A diver descends 20 feet in the water from the boat at the surface of a lake. He then rose 12 feet and descends another 18 feet. At this point what is his depth in water?

Answer 1

Let the depth descended be denoted by negative symbol and the depth ascended be denoted by a positive sign.

So, he went 20 feet down (-20), then came 12 feet up (+12), then he again went another 18 feet down (-18).

We can find the depth the diver is in by adding the values in brackets:

(-20)+(+12)+(-18)=-20+12-18-8-18=-26.

So, the diver is still 20 feet below the surface of the lake i.e. his depth is 20 feet below the see level.

Answer 2

Answer:

20 feet

Step-by-step explanation:

Let the depth descended be denoted by negative symbol and the depth ascended be denoted by a positive sign.

So, he went 20 feet down (-20), then came 12 feet up (+12), then he again went another 18 feet down (-18).

We can find the depth the diver is in by adding the values in brackets:

(-20)+(+12)+(-18)=-20+12-18-8-18=-26.

So, the diver is still 20 feet below the surface of the lake i.e. his depth is 20 feet below the see level.