A diverging mirror of focal length 10cm. If it forms an iamge which is half the size of the object find the position of the image and the object
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Answer:
Given: f=15
u=−10
From mirror formula,
u
1
+
v
1
=
f
1
−10
1
+
v
1
=
15
1
v=6 cm
Image is formed 6 cm to the right of the mirror. Image formed is virtual and erect.
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