Question

Equation of the line of the shortest distance between the lines
x/2 = y/-3 = z/1 and (x-2)/3 = (y-1)/-5 = (z+2)/2​

explain this plss!!!!!

Answer 1

Answer:

Step-by-step explanation: the given lines are

(x-0)/2=(y-0)/-3=(z-0)/3 and (x-2)/3=(y-1)/5=(z-(-2))/2

now shortest distance between the lines is given by |(a2-a1).(b1×b2)|/|b2×b1|

here a1 = 0i^ +0j^ +0k^ ,a2 = 2i^ + 1j^ - 2k^

so a2-a1 = 2i^ + 1j^ - 2k^  now b1=(2,-3,1) b2=(3,-5,2)

b1×b2 = -i^ - j^ - k^

|b1×b2| = √3

S(shortest distance )= |{(2i^ + j^ - 2k^).(-i^-j^-k^)}/√3 |

S = 1/√3

and tada !!!!!!!!!!!!

Answer 2

Step-by-step explanation:

i hope you have understood