a doctor has a prescribed a corrective lens of power +1.2 D. Find the focal length of the lens to be used. Is the lens converging or diverging? what would be the defect of the eye?
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Answered by
33
f is 0.8333m
the lens is convex
defect is hypermetropia
the lens is convex
defect is hypermetropia
Answered by
30
D=1÷f (in meter)
1.2=100÷f
F=120 meter.
Converging lens.
1.2=100÷f
F=120 meter.
Converging lens.
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