Question

A does 75% of a work in 50 days.
he then calls in B and they together
finish the remaining work in 10 357.
days. How long B alone would take
to complete the whole work?
A एक काम का 75%, 50 दिन में पूरा करता
है फिर वो B को बुलाता है और वे दोनों मिलकर
बचा हुआ काम 10 दिन में पूरा करते हैं। पूरा​

Answer 1

Answer:

Let total work to be done = 200 units

Work done by A in 50 days = (75/100) × 200 = 150 units

A's efficiency = 150/50 = 3 units/day...

Remaining work = 200 - 150 =50 units

Let, B's efficiency = x units /day

Now, A & B complete remaining work in 10 days

=> (3+x) ×10 = 50

=> 3+x = 50 ÷ 10 = 5

=> x = 5 - 3 = 2

Therefore ; Time taken by B to complete the whole work alone = 200 ÷ 2 = 100 days