Math, asked by Vanshaj5022, 1 year ago

A dog after traveling 50 km meets a swami who counsels him to go slower. He then proceeds at 3/4 of his former speed and arrives at his destination 35 min late. Had the meeting occurred 24 km further the dog would have reached its destination 25 min late. The speed of dog is:
A.48 kmph
B.36 kmph
C.54 kmph
D.58 kmph

Answers

Answered by DeviIQueen
29

HEYAA ✌

Let the original speed of man be x.

Reduced speed is (3/4)x.

Since meeting after 50kms, and the reducing his speed he reaches his destination 35mins late.

But if the meeting had happened after 74kms(24 kms further) he reaches only 25 mins late.

Therefore the difference of 10 mins happens because of him travelling this 24kms at the different speeds( the original and the reduced)

thus 

24/(3x/4) - 24/x = (10/60) => dividing 10 by 60 to convert into hours

solving this equation we get x = 48km/hr

Ans is A

Answered by Anonymous
4

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A dog after traveling 50 km meets a swami who counsels him to go slower. He then proceeds at 3/4 of his former speed and arrives at his destination 35 min late. Had the meeting occurred 24 km further the dog would have reached its destination 25 min late. The speed of dog is:

A.48 kmph✔✔✔

B.36 kmph

C.54 kmph

D.58 kmph

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