Question

Vinay and Versha run a race with their speed in the ratio of 5:3. They prefer to run on a circular track of circumference 1.5 km. What is the distance covered by Vinay when he passes Versha for the seventh time?
A.25.25 km
B.26.25 km
C.13.2 km
D.14.5 km

Answer 1

Since, the speeds of Vinay and Versha are in the ratio 5:3 i.e. when Vinay covers 5 rounds, then Versa covers 3 rounds, but first time Vinay and Versha meet when Vinay completes {2(1/2)= 2.5} round and Versha completes 1/2 round.
For Vinay to pass Versha seventh time, Vinay would have completed,
= 7*2.5 rounds
Since, each round is 1.5 km, the distance covered by Vinay is,
= 7*2.5*1.5
= 26.25 km.

Answer 2

Answer:

26.25 km

Step-by-step explanation:

let's their speed be 5x and 2x.

Time taken to meet for n th time = n*Circumference/relative speed

relative speed=2x (considering moving in same direction)

then time taken to meet for 7 th time=7*1.5/2x

=5.25/x

distance covered=5x*5.25/x

=26.25 km