Physics, asked by ffcsiva1261, 11 months ago

A dog is 60m away while moving at a constant velocity of 10m/s towards you. where is the dog after 4sec?​

Answers

Answered by itsmedishu
1

Answer:

Answer:after four sec the dog is 20metre away from you..

Answer:after four sec the dog is 20metre away from you..distance of the dog from you: 60m

Answer:after four sec the dog is 20metre away from you..distance of the dog from you: 60mspeed of the dog: 10m

Answer:after four sec the dog is 20metre away from you..distance of the dog from you: 60mspeed of the dog: 10mtime of which dog ran:4sec

Answer:after four sec the dog is 20metre away from you..distance of the dog from you: 60mspeed of the dog: 10mtime of which dog ran:4sechence the distance traveled by the dog: speed×time

Answer:after four sec the dog is 20metre away from you..distance of the dog from you: 60mspeed of the dog: 10mtime of which dog ran:4sechence the distance traveled by the dog: speed×time10×40

Answer:after four sec the dog is 20metre away from you..distance of the dog from you: 60mspeed of the dog: 10mtime of which dog ran:4sechence the distance traveled by the dog: speed×time10×4040m

Answer:after four sec the dog is 20metre away from you..distance of the dog from you: 60mspeed of the dog: 10mtime of which dog ran:4sechence the distance traveled by the dog: speed×time10×4040mdistance remained:60-40=20m

Answered by dewanganajay1875
5

V=u+at

-u=at

-10= a×4

a=- 2.5 m/s^2

v^2=u^2+2as

-u^2=2as

-10×10=2× - 2.5 ×s

s=20 m

It will be 40 m away from me.

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