Question

A dog is barking at a power of 40 pi mW. Its Intensity level of sound emitted at a distance 1 m from the dog is​

Answer 1

intensity level of sound emitted at a distance 1m from the dog is 100 dB.

Given : A dog is barking at a power of 40π mW.

To find : Its intensity level of sound emitted at a distance 1m from the dog.

solution : intensity = power/area = P/4πr²

here , P = 40π mW = 40π × 10¯³ W

r = 1m

so, intensity , I = (40π × 10¯³)/(4π × 1²)

= 10¯² W/m²

now intensity level of sound, β = 10log(I/I0)

here, I0 = 10¯¹² W/m²

so, β = 10log(10¯²/10¯¹²) = 100 dB

Therefore intensity level of sound emitted at a distance 1m from the dog is 100 dB.

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