Math, asked by saranshrock2432, 8 months ago

A dog is chasing a rabbit. Initiallythey are 400 leaps of dog. The time taken by dog totake 4 leaps is equal to 6 leaps taken by rabbit inthat time. Rabbit covers 1.5 m in 1 leap and dogcovers 2.5 m in 1 leap. In how many leaps will thedog catch the rabbit?A dog follows a rabbit. Between the twoThe distance of the dog is 400 leap. 6 jump by rabbitThe time taken to apply the dog's 4 jumpsTime is equal. Rabbit 1.5 meters in a jumpDetermines while the dog is 2.5 meters in a jumpFixes Dog to catch the rabbitHow much leap will have to do?

Answers

Answered by amitnrw
0

Given : A dog is chasing a rabbit. Initially they are 400 leaps of dog.

The time taken by dog to take 4 leaps is equal to 6 leaps taken by rabbit in that time.

Rabbit covers 1.5 m in 1 leap and dog covers 2.5 m in 1 leap.

To Find : In how many leaps will the dog catch the rabbit

Solution:

initial Distance = 400 leaps of dog

1 leap of dog = 2.5 m

Hence Initial Distance = 400 * 2.5  = 1000 m

Let say  n leaps  of dog ,  dog catch the rabbit.

4 leap  of dog  =  6 leap of rabbit

(4 * 2.5 = 10 m) of dog  =  (6 * 1.5 = 9 m) of Rabbit

=> for every 4 leap of dog  , dogs cover 10 - 9 = 1 m  extra distance

=> 4 * 1000  = 4000 leap of dog , dog will cover = 1000 m extra distance

Hence 4000 leap of dog  

in 4000 leaps   the dog will catch the rabbit

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