A domestic circuit has 5A fuse. How many bulbs of rating 100W, 220V can be safely used in this circuit? Justify your answer.
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Answered by
1
Explanation:
p=200W
v=220v
But p=i^2 r
thus
i^2=200/220
i=0.953
that iz the current drawn by one bulb
now total number of bulbs that could be safely used is
5=n×0.953
n=4.8 which can be approximated to 5
thus 5 bulbs can be used that will draw a current less than 5A
Answered by
3
Answer:see the attachment you will find of this question
A domestic circuit has 5A fuse. How many bulbs of rating 100W, 220V can be safely used in this circuit. Justify your answer.
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