Question

A domestic lighting circuit has a fuse of 5 A. If the mains supply is at 230 V, calculate the maximum number of 36 W tube-lights that can be safely used in this circuit.

Answer 1

Explanation:

Hi Shikhar your answer is :-

Answer 2

Answer:

The maximum number of 36 W tube-lights that can be safely used in this circuit = 31

Explanation:

As per the question,

Given data are:

Voltage supply = 230 V

Current passing through circuit = 5 A

Power consumed by one tube light = 36 W

Let the total number of tube-light  = n

Therefore,

Total power consumed = 36 × n W

Now, we have the formula

Power = Voltage × Current

Put all the values in this formula, we get

36 × n = 230 × 5

⇒ n = 31.99

Since the number of tube-light can not be in fraction,

Hence, n =31

Therefore, the maximum number of 36 W tube-lights that can be safely used in this circuit = 31