A double convex lens has two surfaces of equal radii 'R' and refractive index n = 1.5, find the focal length 'f'
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Answer:
Given
Radius of curvature =R
focal length =f
Refractive index, μ=1.5
From lens maker's formula
f
1
=(μ−1)[
R
1
1
−
R
2
1
]
f
1
=(1.5−1)[
R
1
+
R
1
]
=0.5×
R
2
f
1
=
R
1
f=R
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