Question

A dragster accelerates to a speed of 112m/s over a distance of 398m. Determine the acceleration (assume uniform) of a dragster.

Answer 1

we know that acceleration is equal to v^2-u^2=2as
=112×112-0=2×a×398
=12544-0=796s
s=12544/796
s=15.758794 m/s^2

Answer 2

Answer:-

Given:-

➽ Initial velocity (u) = 0 m/s

➽ Final velocity (v) = 112 m/s

➽ Distance travelled (s) = 398 m

To Find:-

Acceleration (a) of the dragster.

___________...

We know,

➽ 2as = v² - u²

➽ a = v²/2s (Since u = 0)

where,

• a = Acceleration,
• s = Distance travelled,
• v = Final velocity &
• u = Initial velocity.

∴ a = (112 m/s)²/(2 × 398m)

➵ a = (12544 m²/s²)/796m

➵ a ≈ 15.75 m s^-2 ...(Ans.)