Question

A dragster accelerates to a speed of 11m/s over a distance of 398m . Determine the acceleration (assumed uniform) of the dragster

Answer 1

Given :

▪ Initial velocity = zero

▪ Final velocity = 11m/s

▪ Distance travelled = 398m

To Find :

▪ Acceleration of dragster.

Concept :

☞ In this question, Acceleration has said to be uniform throughout the motion, we can easily apply third equation of kinematics to solve this question.

✴ Third equation of kinematics :

↗ v² - u² = 2as

where,

▪ v denotes final velocity

▪ u denotes initial velocity

▪ a denotes acceleration

▪ s denotes distance

Calculation :

→ v² - u² = 2as

→ (11)² - (0)² = 2a(398)

→ 121 = 796a

→ a = 121/796

→ a = 0.15m/s²

Answer 2

$\huge\sf\pink{Answer}$

☞ Acceleration = 0.15 m/s²

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$\huge\sf\blue{Given}$

✭ Final Velocity (v) = 11 m/s

✭ Initial Velocity (u) = 0 m/s [assume]

✭ Distance Covered (s) = 398 m

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$\huge\sf\gray{To \:Find}$

◈ The Acceleration of the dragster?

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So, Here we may use the third Equation of Motion,that is

$\underline{\boxed{\sf v^2 - u^2 = 2as}}$

Where,

◕ v = Final Velocity

◕ u = Initial Velocity

◕ a = Acceleration

◕ s = Distance Travelled

Substituting the given values,

»» $\sf (11)^2- (0)^2 = 2 \times a \times 398$±

»» $\sf 121 - 0 = 796a$

»» $\sf 121 = 796a$

»» $\sf \dfrac{121}{796} = a$

»» $\sf \orange{0.15 \ m/s^2}$

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