A drawer contains red socks and black socks and number of black socks are even
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Answer:
Let n = total number of socks
n1 = number of red socks
n2= number of black socks
n1+n2=n
P(2 red)= (n1C2)/(nC2) = [n1!/(n1-2)!2]/[n!/(n-2)!/2]
= n1(n1-1)/(n(n-1))=1/2
If n1=3 then n1(n1-1)=6
then n(n-1)=12 then n=4 then n2=4-3=1
Answer: n=4 (3 red socks and 1 black sock)
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