A drilling operation is to be performed with a 12.7 mm diameter twist drill in a steel work part. The hole is a blind hole at a depth of 60mm and the point angle is 118°. The cutting speed is 25 m/min and the feed is 0.30 mm/rev. Determine (a) the cutting time to complete the drilling operation, and (b) metal removal rate during the operation, after the drill bit reaches full diameter.
Answers
Answer:
158.8 is the removal rate for this question
Given:
Diameter of twist drill = 12.7mm
Depth of hole = 60mm
Point angle = 118°
Cutting speed = 25m/min
Feed = 0.3mm/rev
To find:
Cutting time.
Metal Removal Rate
Solution:
The rotational speed of the drill is given by the formula:
where are the rotational speed, cutting speed and the diameter of the drill respectively
Here, the cutting speed is in metres whereas the diameter is expressed in millimetres. Hence,
Next, we solve for the feed rate which is given by the formula,
where are the feed rate, rotational speed and feed of the drill respectively
To determine the cutting time, we consider the formula as shown below:
where, are the cutting time, depth of hole drilled and feed rate of the drill.
Thus, the cutting time to complete the drilling operation is 0.3192 min.
The rate of metal removal is given by the formula:
where, is the metal removal rate
On converting to seconds,
Thus, the metal removal rate during the operation, after the drill bit reaches full diameter is 396.86mm³/s.
(a) The cutting time to complete the drilling operation is 0.3192 min.
(b) The metal removal rate during the operation, after the drill bit reaches full diameter is 396.86mm³/s.