Math, asked by rishimenon9965, 19 hours ago

Factorise by using suitable identity: 4a2 – 9b2

Answers

Answered by swetaleenadas69
0

Answer:

-5ab2

Hope it helps to u

Hope it helps to u

Answered by jpguruji305
0

Answer:

4a2−9b2

=(2a)2−(3b)2

=(2a+3b)(2a−3b)

Step-by-step explanation:

Factoring: 4a2-9b2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 4 is the square of 2

Check : 9 is the square of 3

Check : a2 is the square of a1

Check : b2 is the square of b1

Factorization is : (2a + 3b) • (2a - 3b)

Final result :

(2a + 3b) • (2a - 3b)

Note :

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