Question

A driver accelerates his car at the rate of 2.4m/s^2 and then at the rate of 1.6m/s^2. What will be the ratio of the two forces exerted by the engine in the two cases?

Answer 1

F1 be the force in first case
F1=m×(2.4)

DE be the force in the second case
F2=m×(1.6)

$\frac{f1}{f2} = \frac{3}{2}$
so F1:F2=3:2