A driver accelerates his car first at the rate of 2.8 m/s2 and then at the rate of 1.4 m/s2.The ratio of two force exerted by the engine in two cases will be:-
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Answer:
considering mass of car are equal we have F=ma
F
2
F
1
=
ma
2
ma
1
=
1.2
1.8
=
2
3
I hope it's help you
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