a driver driving a truck at a constant speed of 20m/s suddenly saw a parked car ahead of him by 95m. He could apply brake after sometime to produce retardation of 2.5m/s.An accident was avoided. his reaction time is
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Answer:
The reaction time= 11.832 seconds
Explanation:
Let us first calculate the time needed for the truck to come to rest , that is final velocity v=0 intial velocity u=20m/s, retardation=2.5m/s²
time taken t
v=u- a×t
t= 20÷2.5
t=8s
s= u×t- (a×t²)÷2
95= 20t- 1.25t²
1.25t² -20t -95=0
t=19.8s, is the maximum time available to avoid the accident and the time needed to bring the vehicle to rest is 8s
therefore the reaction time of the driver = 19.8 - 8 =11.832 s
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